The momentum of a photon of energy 1 MeV in kg-m/s, will be

Options

A. `5 xx 10^(-22)`
B. `0.33 xx 10^(6)`
C. `7 xx 10^(-24)`
D. `10^(-22)`

Answer

1

Explanation

Energy of photon , 1MeV Momentum of photon, `P = (E )/( C)`
`thereforeP=(E)/(C)=(1xx10^(6)xx1.6xx10^(-19)j)/(3xx10^(8)ms^(-1))=0.53xx10^(-21)`
`cong5xx10^(-22)m//s`