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Evaluate int(1)/(1+sinx)dx....

Evaluate `int(1)/(1+sinx)dx`.

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AI Generated Solution

To evaluate the integral \(\int \frac{1}{1 + \sin x} \, dx\), we can use a technique called rationalization. Here’s the step-by-step solution: ### Step 1: Rationalize the Denominator We start by multiplying the integrand by \(\frac{1 - \sin x}{1 - \sin x}\): \[ \int \frac{1}{1 + \sin x} \, dx = \int \frac{1 - \sin x}{(1 + \sin x)(1 - \sin x)} \, dx \] ...
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Knowledge Check

  • int(1)/(1+sinx+cosx)dx=

    A
    `log(1-tan.(x)/(2))+c`
    B
    `log(1+tan.(x)/(2))+c`
    C
    `log(2+tan.(x)/(2))+c`
    D
    `log(2-tan.(x)/(2))+c`
  • int(1)/(1+sinx+cosx)dx=

    A
    `log[1-tan((x)/(2))]+c`
    B
    `log[1+tan((x)/(2))]+c`
    C
    `log[2+tan((x)/(2))]+c`
    D
    `log[2-tan((x)/(2))]+c`
  • int(1)/(sinx-cosx)dx=

    A
    `(1)/(sqrt2)log[tan((pi)/(4)-(x)/(8))]+c`
    B
    `(1)/(sqrt2)log[cot((pi)/(4)-(x)/(8))]+c`
    C
    `(1)/(sqrt2)tan((x)/(2)-(pi)/(8))+c`
    D
    `(1)/(sqrt2)log[tan((x)/(2)-(pi)/(8))]+c`
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