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Evaluate int e^(x)((1-sinx)/(1-cosx))dx....

Evaluate `int e^(x)((1-sinx)/(1-cosx))dx.`

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To evaluate the integral \[ \int e^{x} \left(\frac{1 - \sin x}{1 - \cos x}\right) dx, \] we can start by rewriting the integrand. ...
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inte^(x)(1-sinx)/(1-cosx)dx=

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Knowledge Check

  • inte^(x)((1+sinx)/(1+cosx))dx=

    A
    `e^(x)tan(x)/(2)+C`
    B
    `e^(x)cot(x)/(2)+C`
    C
    `e^(x)sinx+C`
    D
    `e^(2)cosx+C`

  • inte^(x)((1+sinx)/(1+cosx))dx=?

    A
    `e^(x)"sin"(x)/(2)+C`
    B
    `e^(x)"cos"(x)/(2)+C`
    C
    `e^(x)"tan"(x)/(2)+C`
    D
    none of these

  • inte^((x)/(2))((2-sinx)/(1-cosx))dx=

    A
    `2e^((x)/(2))cot((x)/(2))+c`
    B
    `-2e^((x)/(2))cot((x)/(2))+c`
    C
    `e^((x)/(2))cot((x)/(2))+c`
    D
    `-e^((x)/(2))cot((x)/(2))+c`

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    int e^x((1-sinx)/(1-cosx)) dx is equal to

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