If a function satisfies the relation `f(x) f''(x)-f(x)f'(x)=(f'(x))^(2) AA x in R and f(0)=f'(0)=1,` then
Number of roots of the equation `f(x)=e^(x)` is

Options

A. 0
B. 1
C. 2
D. infinite

Answer

B

Explanation

`f(x)f''(x)-f(x)f'(x)=(f'(x))^(2)`
` :. (f''(x)-f'(x))/(f'(x))=(f'(x))/(f(x))`
`implies(f''(x))/(f'(x))-1=(f'(x))/(f(x))`
On integrating both sides w.r.t. x, we get
`log_(e)(f'(x))-x=log_(e)f(x)+c`
`f(0)=f'(0)=1`
` :. 0-0=0+c`
` :. c=0`
` :. log_(e)(f'(x))-x=log_(e)f(x)`
`implieslog_(e)(f'(x))-log_(e)f(x)=x`
`implies (f'(x))/(f(x))=e^(x)`
On integrating both sides w.r.t. x. we get
` :. log_(e)f(x)=e^(x)+c`
Putting `x=0`, we get `c= -1`
` :. log_(e)f(x)=e^(x)-1`
` :. f(x)=e^(e^(x)-1)`