The minimum value of `atan^2x+bcot^2x` equals the maximum value of `asin^2theta+bcos^2theta` where `a > b > 0.` The `a/b` is 2 (b) 4 (c) 6 (d) 8

Answer

2

Explanation

Minimum value of `atan^2+bcot^2x" is " 2sqrt(ab)`.
And maximum value of `asin^2theta+bcos^2theta" is "a`.
`( :'asin^2theta+bcos^2theta=(a-b)sin^2theta+b)`
According to equestion, `a=2sqrt(ab)`
`:. a=4b`