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A particle moves on a circular path of r...

A particle moves on a circular path of radius 'r'. It completes one revolution in 40s. Calculate distances displacement in 2 min 20 s.

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To solve the problem, we will follow these steps: ### Step 1: Convert the time from minutes and seconds to seconds. The total time given is 2 minutes and 20 seconds. - Convert 2 minutes to seconds: \[ 2 \text{ minutes} = 2 \times 60 = 120 \text{ seconds} \] ...
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Knowledge Check

  • A cyclist moving on a circular track of radius 40 m completes half a revolution in 40 s. Its average velocity is

    A
    zero
    B
    `4pi ms^(-1)`
    C
    `2ms^(-1)`
    D
    `8pi ms^(-1)`
  • A body move in a circular path of radius 20 cm. If it completes two and a half revolution along the circular path, the distance and displacement of the body are

    A
    40 cm,0
    B
    314 cm,0
    C
    314 cm, 40 cm
    D
    628 cm, 314 cm
  • A cyclist moving on a circular track of radius 40 m completes half a revolution in 40 sec. Its average velocity is :

    A
    zero
    B
    `4 pi m//s^2`
    C
    `2 m//s`,
    D
    `8 pi m//s`
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