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If the error in the measurement of radiu...

If the error in the measurement of radius of a sphere in `2%` then the error in the determination of volume of the spahere will be

A

`8%`

B

`2%`

C

`4%`

D

`6%`

Text Solution

Verified by Experts

The correct Answer is:
D

`V = (4)/(3) pir^(3) rArr (DeltaV)/(V) xx 100 = (3Delta r)/(r ) xx 100 = 3(2%) = 6%`
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