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Two oxides of metal M have 27.6% and 30%...

Two oxides of metal M have `27.6%` and `30%` oxygen by weight. If the formula of the first oxide is `M_(3)O_(4)` what is the formula of second oxide?

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Oxide (A) : Oxygen `22.6%,` 4.O. atoms
`"Oxide (B) : Oxygen 30%, Metal 70%"`
`"Number of .O. atoms"=(30)/(27.6)xx4=4.35`
`"Number of .M. atoms"=(70)/(72.4)xx3=2.9`
Ratio of M and O atoms is oxide
`B=2.9:4.35=2:3`
Formula of the second oxide is `M_(2)O_(3)`
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