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An oxide of iron contains 69.94% Fe and ...

An oxide of iron contains `69.94% Fe` and `30.06%O`. Determine its E.F. `(Fe = 55.85, O = 16.0)`

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`"Element Fe O"`
`"% composition = 69.94 30.06"`
`"Mole retio"=(69.94)/(55.85)=1.25(30.06)/(16)=1.88`
`"simple mole ratio"(1.25)/(1.25)=1xx2(1.88)/(1.25)=1.5xx2=3`
whole number ratio`" 2 3"`
`E.F.=Fe_(2)O_(3)`
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