How many grams of `80%` pure marble stone on calination can give 14 grams of quick lime ?

Explanation

`CACO_(3)rarrCaO+CO_(2)`
`{:(100g,56 g),(?14g,):}`
`(14xx100)/(56)=25g`
Percentage purity is only `80%`
80 g of `CaCO_(3)=100g` of marble stone.
`25g" of "CaCO_(3)=?`
`(25)/(80)xx100=31.25g`