The volume of `O_(2)` at S.T.P required for completely burnt out 100 ml. of ethane is

Explanation

`C_(2)H_(6)+(7)/(2)O_(2)rarr2CO_(2)+3H_(2)O`
1 ml. of ethane required 7/2 ml. of oxygen
`"Volume of "O_(2)" required to burn 100 ml of "C_(2)H_(6)=(100)/(1)xx(7)/(2)=350 ml`