What mass of `CaCO_(3)` is required to react completely with 25ml of 0.75 M HCl?

Explanation

To determine the mass of calcium carbonate (CaCO₃) required to react completely with 25 mL of 0.75 M hydrochloric acid (HCl), we can follow these steps:

### Step 1: Write the balanced chemical equation
The reaction between calcium carbonate and hydrochloric acid can be represented as:
\[ \text{CaCO}_3 (s) + 2 \text{HCl} (aq) \rightarrow \text{CaCl}_2 (aq) + \text{H}_2\text{O} (l) + \text{CO}_2 (g) \]

### Step 2: Calculate the number of moles of HCl
We can use the formula for molarity:
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