How many moles of lead nitrate is needed to produce 224 litre of oxygen at NTP?

Explanation

To determine how many moles of lead nitrate are needed to produce 224 liters of oxygen at Normal Temperature and Pressure (NTP), we can follow these steps:

### Step 1: Understand the relationship between moles and volume at NTP
At NTP, 1 mole of any gas occupies a volume of 22.4 liters. Therefore, to find the number of moles of oxygen (O₂) produced from a given volume, we can use the formula:

\[ \text{Number of moles} = \frac{\text{Volume (liters)}}{22.4 \text{ L/mol}} \]
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