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A solution is prepared by adding 360 g o...

A solution is prepared by adding 360 g of glucose to 864 g of water. Calculate mole fraction of glucose (molar mass of glucose = 180).

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`"No. of moles of glucose "=(360)/(180)=2`
`"No. of moles of water"=(864)/(18)=48`
`therefore" Mole fraction of glucose"=`
`(2)/(2+48)=(2)/(50)=(1)/(25)=0.04`
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NARAYNA-SOME BASIC CONCEPTS OF CHEMISTRY-EXERCISE - IV
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