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How many moles and how many grams of HCl...

How many moles and how many grams of HCl are present in `250cm^(3)` of 0.5M HCl solution ?

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Verified by Experts

Molecular mass of HCl=36.5
Molarity`=0.5 M="0.5 Mol L"^(-1)`
`"Volume of solution = 250 cm"^(3)`
So, number of moles in `"250 cm"^(3)=MV_(L)=(0.5xx250)/(1000)=(0.5)/(4)="0.125 moles"`
`"Weight of HCl dissolved "="number of moles of HCl"xx36.5`
`=0.125xx36.5`
`=4.5625g`
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