`"200 ml "(N)/(10)H_(2)SO_(4)` is mixed into 300 `ml(N)/(100)NaOH`. Calculate normality of resulting mixture.

Explanation

To find the normality of the resulting mixture when 200 ml of \( \frac{N}{10} H_2SO_4 \) is mixed with 300 ml of \( \frac{N}{100} NaOH \), we can follow these steps:

### Step 1: Identify the given values
- Volume of \( H_2SO_4 (V_1) = 200 \, \text{ml} \)
- Normality of \( H_2SO_4 (N_1) = \frac{N}{10} = 0.1 \, N \)
- Volume of \( NaOH (V_2) = 300 \, \text{ml} \)
- Normality of \( NaOH (N_2) = \frac{N}{100} = 0.01 \, N \)

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