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If 100 mL of 1NH(2)SO(4) is mixed with 1...

If 100 mL of `1NH_(2)SO_(4)` is mixed with 100 mL of 1 M NaOH solution. The resulting solution will be

A

Highly acidic

B

neutral

C

Highly basic

D

Slightly acidic

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The correct Answer is:
To solve the problem of what happens when 100 mL of 1 N H₂SO₄ is mixed with 100 mL of 1 M NaOH, we will follow these steps: ### Step 1: Understand the Normality and Molarity - Given: - H₂SO₄ is a diprotic acid, meaning it can donate 2 protons (H⁺ ions). - The normality (N) of H₂SO₄ is given as 1 N. ### Step 2: Convert Normality to Molarity - The relationship between normality and molarity for acids is given by: \[ \text{Normality (N)} = \text{Molarity (M)} \times n \] where \( n \) is the number of protons that can be donated. - For H₂SO₄, \( n = 2 \): \[ 1 \, \text{N} = \text{Molarity (M)} \times 2 \implies \text{Molarity (M)} = \frac{1}{2} = 0.5 \, \text{M} \] ### Step 3: Calculate Moles of H₂SO₄ and NaOH - Volume of H₂SO₄ = 100 mL = 0.1 L - Molarity of H₂SO₄ = 0.5 M - Moles of H₂SO₄: \[ \text{Moles of H₂SO₄} = \text{Molarity} \times \text{Volume} = 0.5 \, \text{mol/L} \times 0.1 \, \text{L} = 0.05 \, \text{mol} \] - Volume of NaOH = 100 mL = 0.1 L - Molarity of NaOH = 1 M - Moles of NaOH: \[ \text{Moles of NaOH} = \text{Molarity} \times \text{Volume} = 1 \, \text{mol/L} \times 0.1 \, \text{L} = 0.1 \, \text{mol} \] ### Step 4: Determine the Reaction - The balanced chemical reaction between H₂SO₄ and NaOH is: \[ H₂SO₄ + 2 \, NaOH \rightarrow Na₂SO₄ + 2 \, H₂O \] - From the reaction, we see that 1 mole of H₂SO₄ reacts with 2 moles of NaOH. ### Step 5: Determine Limiting Reactant - We have 0.05 moles of H₂SO₄ and 0.1 moles of NaOH. - According to the stoichiometry: - 0.05 moles of H₂SO₄ would require \( 2 \times 0.05 = 0.1 \) moles of NaOH. - Since we have exactly 0.1 moles of NaOH, both reactants will completely react. ### Step 6: Analyze the Resulting Solution - After the reaction, we will have: - Products: Na₂SO₄ (salt) and water. - The resulting solution will contain only the salt (Na₂SO₄) and water, which is neutral. ### Conclusion - The resulting solution will be neutral. ### Final Answer The resulting solution will be **Neutral**. ---
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