The specific heat of an element is 0.214 cal/gm. The atomic weight is nearly

Options

A. 6.6
B. 12
C. 30
D. 65

Explanation

To find the atomic weight of the element using its specific heat, we can apply Dulong-Petit law, which states that the approximate atomic weight (A) of an element can be calculated using the formula:

\[ A \approx \frac{6.4}{\text{Specific Heat}} \]

Given that the specific heat of the element is 0.214 cal/gm, we can substitute this value into the formula.

### Step-by-Step Solution:

1. **Identify the specific heat value**:
- The specific heat of the element is given as 0.214 cal/gm.

2. **Apply the Dulong-Petit law formula**:
- Substitute the specific heat value into the formula:
\[ A \approx \frac{6.4}{0.214} \]

3. **Perform the division**:
- Calculate the value:
\[ A \approx \frac{6.4}{0.214} \approx 29.9 \]

4. **Round the result**:
- Since 29.9 is closer to 30, we can round it to 30.

5. **Check the options**:
- Look for the option that corresponds to the atomic weight of 30.

### Final Answer:
- The atomic weight of the element is approximately **30**.