The vapour density of ethyl alcohol vapour is

Options

A. 46
B. 23
C. 92
D. 69

Explanation

To find the vapor density of ethyl alcohol (C2H5OH), we can follow these steps:

### Step 1: Understand the Concept of Vapor Density
Vapor density is defined as the mass of a certain volume of gas compared to the mass of an equal volume of hydrogen at the same temperature and pressure. The formula for vapor density (VD) is given by:

\[ \text{Vapor Density} = \frac{\text{Molar Mass of the Compound}}{\text{Molar Mass of Hydrogen (H}_2\text{)}} \]

### Step 2: Determine the Molar Mass of Ethyl Alcohol (C2H5OH)
To calculate the molar mass of ethyl alcohol, we need to sum the molar masses of its constituent atoms:

- Carbon (C): 2 atoms × 12 g/mol = 24 g/mol
- Hydrogen (H): 6 atoms × 1 g/mol = 6 g/mol
- Oxygen (O): 1 atom × 16 g/mol = 16 g/mol

Now, add these values together:

\[ \text{Molar Mass of C}_2\text{H}_5\text{OH} = 24 + 6 + 16 = 46 \text{ g/mol} \]

### Step 3: Use the Vapor Density Formula
Now that we have the molar mass of ethyl alcohol, we can substitute it into the vapor density formula. The molar mass of hydrogen (H2) is 2 g/mol.

\[ \text{Vapor Density} = \frac{\text{Molar Mass of C}_2\text{H}_5\text{OH}}{\text{Molar Mass of H}_2} = \frac{46 \text{ g/mol}}{2 \text{ g/mol}} = 23 \]

### Step 4: Conclusion
The vapor density of ethyl alcohol vapor is 23.

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