Number of atoms in 55.85 gram Fe `("at.wt. of Fe = 55.85 g mol"^(-1))` is .

Options

A. Twice that 60 g carbon
B. `6.023xx10^(22)`
C. Half that in 8g He
D. `55.85xx6.023xx10^(23)`

Explanation

To find the number of atoms in 55.85 grams of iron (Fe), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Given Data:**
- Mass of iron (Fe) = 55.85 grams
- Atomic weight of iron (Fe) = 55.85 g/mol

2. **Calculate the Number of Moles of Iron:**
The number of moles can be calculated using the formula:
\[ \text{Number of moles} = \frac{\text{Given mass}}{\text{Molar mass}} \]
Substituting the values:
\[ \text{Number of moles} = \frac{55.85 \text{ g}}{55.85 \text{ g/mol}} = 1 \text{ mol} \]

3. **Use Avogadro's Number to Find the Number of Atoms:**
Avogadro's number (N_A) is approximately \(6.02 \times 10^{23}\) atoms/mol. The total number of atoms can be calculated as:
\[ \text{Number of atoms} = \text{Number of moles} \times N_A \]
Substituting the values:
\[ \text{Number of atoms} = 1 \text{ mol} \times 6.02 \times 10^{23} \text{ atoms/mol} = 6.02 \times 10^{23} \text{ atoms} \]

4. **Final Result:**
Therefore, the number of atoms in 55.85 grams of iron is:
\[ \boxed{6.02 \times 10^{23}} \text{ atoms} \]