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A person adds 1.71 g of sugar (C(12)H(22...

A person adds 1.71 g of sugar `(C_(12)H_(22)O_(11))` in order to sweeten his tea. The number of carbon atoms added are (molecular mass of sugar = 342)

A

`3.6xx10^(22)`

B

`7.2xx10^(21)`

C

`0.05`

D

`6.6xx10^(22)`

Text Solution

Verified by Experts

The correct Answer is:
A

`"No. of C atom = No. of C atoms in molecule"xxnxxN`
`=12xx(1.71)/(342)xx6xx10^(23)`
`=3.6xx10^(22)`
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