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If 1.26 grams of oxalic acid is dissolve...

If `1.26` grams of oxalic acid is dissolved in 250 ml of solution then its normality is

A

0.05

B

0.04

C

0.02

D

0.08

Text Solution

Verified by Experts

The correct Answer is:
D
`N=(w)/(GEW)xx(1000)/("V (in ml)")`
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