Noramlity of `2%` of `H_(2)SO_(4)` solution by volume is nearly

Options

A. 2
B. 4
C. 0.2
D. 0.4

Explanation

To find the normality of a 2% solution of H₂SO₄ by volume, we can follow these steps:

### Step 1: Understand the 2% Solution
A 2% solution by volume means that there are 2 grams of H₂SO₄ in every 100 mL of solution.

### Step 2: Calculate the Molecular Weight of H₂SO₄
The molecular weight (molar mass) of H₂SO₄ can be calculated as follows:
- Hydrogen (H) = 1 g/mol, and there are 2 H atoms: 2 × 1 = 2 g/mol
- Sulfur (S) = 32 g/mol
- Oxygen (O) = 16 g/mol, and there are 4 O atoms: 4 × 16 = 64 g/mol

Adding these together:
\[ \text{Molecular weight of H₂SO₄} = 2 + 32 + 64 = 98 \, \text{g/mol} \]

### Step 3: Calculate the Number of Moles of H₂SO₄
Using the formula for moles:
\[ \text{Number of moles} = \frac{\text{Given weight}}{\text{Molecular weight}} \]
Given weight = 2 g, Molecular weight = 98 g/mol:
\[ \text{Number of moles} = \frac{2 \, \text{g}}{98 \, \text{g/mol}} \approx 0.0204 \, \text{mol} \]

### Step 4: Calculate the Molarity of the Solution
Molarity (M) is defined as moles of solute per liter of solution. Since we have 100 mL of solution, we convert this to liters:
\[ 100 \, \text{mL} = 0.1 \, \text{L} \]
Now, calculate the molarity:
\[ \text{Molarity} = \frac{\text{Number of moles}}{\text{Volume in liters}} = \frac{0.0204 \, \text{mol}}{0.1 \, \text{L}} = 0.204 \, \text{M} \]

### Step 5: Determine the n Factor for H₂SO₄
The n factor for H₂SO₄ is 2 because it can donate 2 protons (H⁺ ions) in a reaction.

### Step 6: Calculate the Normality
Normality (N) is given by the formula:
\[ \text{Normality} = n \times \text{Molarity} \]
Substituting the values:
\[ \text{Normality} = 2 \times 0.204 \, \text{M} = 0.408 \, \text{N} \]

### Conclusion
The normality of a 2% H₂SO₄ solution by volume is approximately **0.4 N**.

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