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Number of gram equivalents of solute in ...

Number of gram equivalents of solute in 100 ml of 5N HCl solution is

A

50

B

500

C

5

D

0.5

Text Solution

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The correct Answer is:
To find the number of gram equivalents of solute in 100 ml of a 5N HCl solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Normality (N)**: Normality (N) is defined as the number of gram equivalents of solute per liter of solution. In this case, we have a 5N HCl solution. 2. **Convert Volume from ml to L**: Since normality is expressed per liter, we need to convert the volume from milliliters to liters. \[ 100 \, \text{ml} = \frac{100}{1000} \, \text{L} = 0.1 \, \text{L} \] 3. **Use the Normality Formula**: The formula for normality is: \[ \text{Normality (N)} = \frac{\text{Number of gram equivalents}}{\text{Volume of solution in liters}} \] Rearranging this formula to find the number of gram equivalents gives us: \[ \text{Number of gram equivalents} = \text{Normality (N)} \times \text{Volume of solution in liters} \] 4. **Substitute the Values**: Now we can substitute the values we have: \[ \text{Number of gram equivalents} = 5 \, \text{N} \times 0.1 \, \text{L} \] 5. **Calculate the Result**: \[ \text{Number of gram equivalents} = 5 \times 0.1 = 0.5 \, \text{gram equivalents} \] ### Final Answer: The number of gram equivalents of solute in 100 ml of 5N HCl solution is **0.5 gram equivalents**. ---

To find the number of gram equivalents of solute in 100 ml of a 5N HCl solution, we can follow these steps: ### Step-by-Step Solution: 1. **Understand Normality (N)**: Normality (N) is defined as the number of gram equivalents of solute per liter of solution. In this case, we have a 5N HCl solution. 2. **Convert Volume from ml to L**: ...
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