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From 320 mg. of O(2), 6.023 xx 10^(20) m...

From 320 mg. of `O_(2), 6.023 xx 10^(20)` molecules are removed, the no. of moles remained are

A

`9xx10^(-3)" moles"`

B

`9xx10^(-2)" moles"`

C

Zero

D

`3xx10^(-3)" moles"`

Text Solution

Verified by Experts

The correct Answer is:
A
`"320 mg of CO"_(2)=(320xx10^(-3))/(32)" moles"=10^(-2)" moles"`
`6.023xx10^(20)" molecules"`
`CO_(2)=(6.023xx10^(20))/(6.023xx10^(23))" moles "=10^(-3)" moles"`
`therefore 10^(-2)-10^(-3)`
`=10xx10^(-3)-1xx10^(-3)`
`=10^(-3)(10-1)=9xx10^(-3)" moles"`
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