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1.5g CdCl(2) was formed to contain 0.9g ...

1.5g `CdCl_(2)` was formed to contain 0.9g Cd. Calculate MO, the atomic weight of Cd.

A

118

B

112

C

106.5

D

53.25

Text Solution

Verified by Experts

The correct Answer is:
C
`"% Cd in Cd "Cl_(2)(60%)`
`%Cl_(2)" in Cd "Cl_(2)(40%)`
`40%" has - Atwt 71"`
`60% - 106.5`
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