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Two containers P and Q of equal volume (...

Two containers P and Q of equal volume (1 litre each) contain 6 g of `O_(2)` and `SO_(2)` respectively at 300 K and 1 atmosphere. Then

A

Number of molecules in P ie less than that in Q

B

Number of molecules in Q is less that in P

C

Number of molecules in P and Q are same

D

None of these

Text Solution

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The correct Answer is:
To solve the problem, we need to calculate the number of moles of \( O_2 \) and \( SO_2 \) in containers P and Q respectively, and then determine the number of molecules in each container. ### Step-by-Step Solution: 1. **Determine the number of moles of \( O_2 \) in container P:** - Given mass of \( O_2 \) = 6 g - Molecular weight of \( O_2 \) = 32 g/mol (since \( O \) has an atomic weight of 16, and \( O_2 \) has 2 oxygen atoms) - Number of moles of \( O_2 \) = \( \frac{\text{mass}}{\text{molecular weight}} = \frac{6 \, \text{g}}{32 \, \text{g/mol}} = 0.1875 \, \text{mol} \) 2. **Determine the number of moles of \( SO_2 \) in container Q:** - Given mass of \( SO_2 \) = 6 g - Molecular weight of \( SO_2 \) = 64 g/mol (Sulfur has an atomic weight of 32 and each oxygen has an atomic weight of 16, so \( 32 + 2 \times 16 = 64 \)) - Number of moles of \( SO_2 \) = \( \frac{6 \, \text{g}}{64 \, \text{g/mol}} = 0.09375 \, \text{mol} \) 3. **Calculate the number of molecules in each container:** - Using Avogadro's number \( N_A = 6.022 \times 10^{23} \, \text{molecules/mol} \) - Number of molecules in container P (for \( O_2 \)): \[ \text{Number of molecules in P} = 0.1875 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \approx 1.13 \times 10^{23} \, \text{molecules} \] - Number of molecules in container Q (for \( SO_2 \)): \[ \text{Number of molecules in Q} = 0.09375 \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \approx 5.64 \times 10^{22} \, \text{molecules} \] 4. **Comparison of the number of molecules:** - From the calculations, we find that: - Number of molecules in P \( \approx 1.13 \times 10^{23} \) - Number of molecules in Q \( \approx 5.64 \times 10^{22} \) - Therefore, the number of molecules in container P is greater than that in container Q. ### Conclusion: - The number of molecules in container P is greater than in container Q. ### Final Answer: - The correct option is: "Number of molecules in Q is less than that of P."

To solve the problem, we need to calculate the number of moles of \( O_2 \) and \( SO_2 \) in containers P and Q respectively, and then determine the number of molecules in each container. ### Step-by-Step Solution: 1. **Determine the number of moles of \( O_2 \) in container P:** - Given mass of \( O_2 \) = 6 g - Molecular weight of \( O_2 \) = 32 g/mol (since \( O \) has an atomic weight of 16, and \( O_2 \) has 2 oxygen atoms) - Number of moles of \( O_2 \) = \( \frac{\text{mass}}{\text{molecular weight}} = \frac{6 \, \text{g}}{32 \, \text{g/mol}} = 0.1875 \, \text{mol} \) ...
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