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The weight of a molecule of the compound...

The weight of a molecule of the compound`C_(60)H_(122)` is

A

`1.4xx10^(-21)g`

B

`1.09xx10^(-21)g`

C

`5.025xx10^(23)g`

D

`16.023xx10^(23)g`

Text Solution

Verified by Experts

The correct Answer is:
A
`"wt of 1 mole of "C_(60)H_(122)=60xx12+122xx1`
`=720+122`
`="842 gms"`
`therefore 6xx10^(23)" molecules ………….. 842 gms"`
`"1 molecule …………………?"`
`=(842)/(6xx10^(23))=140xx10^(-23)=1.4xx10^(-21)" gms"`
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