Home
Class 11
CHEMISTRY
0.126 g of acid required 20 mL of 0.1 N ...

0.126 g of acid required 20 mL of 0.1 N NaOH for complete neutralisation. The equivalent mass of an acid is

A

52.7

B

158

C

63

D

79

Text Solution

Verified by Experts

The correct Answer is:
C
`"no of equivalents of acid "="no of equivalents of base"`
`("wt of acid")/("G.Eq. wt of acid")=0.1xx20xx10^(-3)`
`therefore E=(0.126)/(0.1xx20xx10^(-3))=63`
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (C.W)(METHODS OF EXPRESSING CONCENTRATIONS)|14 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (H.W)(LAWS OF CHEMICAL COMBINATIONS)|14 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    NARAYNA|Exercise EXERCISE - II (C.W)(PERCENTAGE WEIGHT OF ELEMENTS IN COMPOUNDS MOLECULAR FORMULA & EMPERICAL FORMULA)|13 Videos

  • SOME BASIC CONCEPTS IN CHEMISTRY STOICHIOMETRY (PART-I)

    NARAYNA|Exercise All Questions|555 Videos

  • SOME BASIC PRINCIPLES AND TECHNIQUES

    NARAYNA|Exercise EXERCISE -IV (QUALITATIVE AND QUANTITATIVE ANALYSIS OF ORGANIC OF COMPOUNDS)|8 Videos

Similar Questions

Explore conceptually related problems

0.14 gm of an acid required 12.5 ml of 0.1 N NaOH for complete neuturalisation.The equivalent mass of the acid is:

The ammonia evolved from the treatment of 0.30 g of an organic compound for the estimation of nitrogen was passed in 100 mL of 0.1 M sulphuric acid . The excess of acid required 20 mL of 0.5 M NaOH solution for complete neutralisation.The organic compound is