1.0 g of a metal combines with 8.89 g of Bromine. Equivalent weight of metal is nearly (at.wt. of Br = 80)

Options

A. 8
B. 9
C. 10
D. 7

Explanation

To find the equivalent weight of the metal, we can use the following steps:

### Step 1: Understand the concept of equivalent weight
The equivalent weight of a substance is defined as the mass of the substance that combines with or displaces 1 mole of hydrogen or 1 mole of electrons in a reaction. For metals, it can often be calculated using the formula:

\[ \text{Equivalent weight} = \frac{\text{Molar mass}}{n} \]

where \( n \) is the number of moles of electrons exchanged or the valency of the metal.

### Step 2: Calculate the equivalent weight of bromine
Given that the atomic weight of bromine (Br) is 80 g/mol, we can find the equivalent weight of bromine. Bromine typically forms a diatomic molecule (Br2), so when it reacts, it usually takes up 1 mole of electrons (or combines with 1 mole of another element).

\[ \text{Equivalent weight of Br} = \frac{\text{Atomic weight of Br}}{n} = \frac{80}{1} = 80 \text{ g/equiv} \]

### Step 3: Calculate the number of equivalents of bromine
Using the mass of bromine that combines with the metal, we can calculate the number of equivalents of bromine:

\[ \text{Number of equivalents of Br} = \frac{\text{mass of Br}}{\text{equivalent weight of Br}} = \frac{8.89 \text{ g}}{80 \text{ g/equiv}} = 0.111125 \text{ equiv} \]

### Step 4: Calculate the equivalent weight of the metal
Since 1 g of the metal combines with the bromine, the number of equivalents of the metal will be equal to the number of equivalents of bromine:

\[ \text{Number of equivalents of metal} = 0.111125 \text{ equiv} \]

Now, we can find the equivalent weight of the metal:

\[ \text{Equivalent weight of metal} = \frac{\text{mass of metal}}{\text{number of equivalents of metal}} = \frac{1 \text{ g}}{0.111125 \text{ equiv}} \approx 9.0 \text{ g/equiv} \]

### Final Answer
The equivalent weight of the metal is approximately **9.0 g/equiv**.

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