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When a certain metal was irradiated wit...

When a certain metal was irradiated with light of frequency `4.0 xx 10^(16)s^(-1)` the photoelectrons emitted had three times the kinetic energy as the kinetic energy of photoelectrons emitted when the metal was irradited with light of frequency `2.0 xx 10^(16) s^(-1)`. Calculate the critical frequency `(nu_(0))` of the metal.

A

`2.0 xx 10^(16) s^(-1)`

B

`1.6 xx 10^(16) s^(-1)`

C

`3.0 xx 10^(16) s^(-1)`

D

`4.2 xx 10^(16) s^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`(K.E_2)/(K.E_1) = (v_2- v_0)/(v_1 - v_0)`
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