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If the diameter of a carbon atom is 0.15...

If the diameter of a carbon atom is `0.15 nm`, calculate the number of carbon atom which can be placed side by side in a straight line length of scale of length `20 cm` long.

A

`13.3 xx 10^(9)`

B

`1.33 xx 10^(9)`

C

`6.2 xx 10^(9)`

D

`1.33 xx 10^(7)`

Text Solution

Verified by Experts

The correct Answer is:
B
No. of carbon items that can be placed in a straight line `= ("length")/("diameter")`
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