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Light of wavelength lambda strikes a met...

Light of wavelength `lambda` strikes a metal surface with intensity `X` and the metal emits `Y` electrons per second of average energy `Z`. What will happen to `Y` and `Z` if `X` is havled?

A

y will be doubled and z will become half

B

y will remain same and z will be doubled

C

Both y and z will be doubled

D

y will be doubled but z will remain same

Text Solution

Verified by Experts

The correct Answer is:
D
no. of photo electrons ejected `alpha` intensity of radiation but KE is independent of intensity of mediation.
`K.E = h (?-?_0) p (1)/(2) mv^(2) = h(?-?_0)`
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