Home
Class 11
CHEMISTRY
The ejection of the photoelectron from t...

The ejection of the photoelectron from the silver metal in the photoelectric effect exeriment can be stopped by applying the voltage of `0.35 V` when the radiation `256.7 nm` is used. Calculate the work function for silver metal.

A

4.48 ev

B

3.35 ev

C

44.8 ev

D

22.4 ev

Text Solution

Verified by Experts

The correct Answer is:
A
`= (hc)/(lambda) - K.E.= (6.625 xx 10^(-34) xx 3 xx 10^(8) )/(256.7 xx 10^(-9))-0.35`
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV H-SPECTRUM|7 Videos

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV BOHR.S ATOMIC MODEL|4 Videos

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV ELECTROMAGNETIC RADIATION|12 Videos

  • STATES OF MATTER

    NARAYNA|Exercise A & R TYPE QUESTIONS|16 Videos

  • THERMODYNAMICS

    NARAYNA|Exercise Assertion- Reason|5 Videos

Similar Questions

Explore conceptually related problems

Ejection of the photoelectron from metal in the photoelectric effect experiment can be stopped by applying 0.5 V when the radiation of 250 nm is used. The work function of the metal is

In photoelectric effect, the work function of a metal is 3.7 eV. The emitted electron can be stopped by applying a potential of 1.8 V. Then

In photoelectric effect the work function of a metal is 3.5 eV. The emitted electrons can be stopped by applying a potential of –1.2 V. Then

The work function of a metal is hv_0 . Light of frequency v falls on this metal. The photoelectric effect will take place only if

Energy required to stop the ejection of electrons from certain metal plate was found to be 0.2 eV when an electromagnetic radiation of 330 nm was made to fall on it the work function of the metal is

Photoelectric effect is described as the ejection of electrons from the surface of a metal when: