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Ionisation energy of He^(+) " is " 19.6 ...

Ionisation energy of `He^(+) " is " 19.6 xx 10^(-18)J "atom"^(-1)`. The energy of the first stationary state `(n = 1)` of `Li^(2+)` is

A

`4.41 xx 10^(-16) J "atom"^(-1)`

B

`-4.41 xx 10^(-17) J "atom"^(-1)`

C

`-2.2 xx 10^(-15) J "atom"^(-1)`

D

`-8.83 xx 10^(-17) J"atom"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`I.E = - E_1 E_(n) prop (z^2)/(n^2) rArr ((E_1)_(He^(+)))/((E_1)_(Li^(+2)))=((z_(He^(+))^2))/((z_(Li^(+2))^2)`
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