Which of the following is miscible with water

Options

A. `CS_2`
B. `C_2H_5OH`
C. `C Cl_4`
D. `CH Cl_3`

Explanation

To determine which of the given compounds is miscible with water, we need to analyze the polarity of each compound and its ability to interact with water, which is a polar solvent.

### Step-by-Step Solution:

1. **Identify the Compounds**: The compounds given are:
- CH2CO2 (Acetic acid)
- C2H5OH (Ethanol)
- CCl4 (Carbon tetrachloride)
- CHCl3 (Chloroform)

2. **Understand Miscibility**: Miscibility refers to the ability of a substance to mix with another substance in any proportion without separating into two phases. For a solute to be miscible in water, it should preferably be polar or capable of forming hydrogen bonds with water.

3. **Analyze Each Compound**:
- **CH2CO2 (Acetic acid)**: This compound is polar due to the presence of the carboxyl group (-COOH), which can form hydrogen bonds with water. Therefore, it is miscible with water.

- **C2H5OH (Ethanol)**: Ethanol is also polar and has a hydroxyl group (-OH) that can form strong hydrogen bonds with water. Thus, ethanol is miscible with water.

- **CCl4 (Carbon tetrachloride)**: CCl4 is a non-polar molecule. It does not interact well with polar solvents like water, making it immiscible.

- **CHCl3 (Chloroform)**: Chloroform is polar due to the presence of chlorine atoms, but it does not form strong hydrogen bonds with water as it lacks a highly electronegative atom directly bonded to hydrogen. Therefore, it has limited miscibility with water.

4. **Conclusion**: Among the given compounds, both CH2CO2 (Acetic acid) and C2H5OH (Ethanol) are miscible with water. However, since the question asks for the option that is miscible, the best answer is **C2H5OH (Ethanol)**, as it forms strong hydrogen bonds with water.

### Final Answer:
**C2H5OH (Ethanol)** is miscible with water.