Odd electron bond is present in

Options

A. NO
B. `NO_2`
C. `CIO_2`
D. All

Answer

To determine which molecule has an odd electron bond, we need to analyze the total number of valence electrons in each option provided. An odd electron bond occurs when there is at least one unpaired electron after forming bonds. Let's go through the options step by step.

### Step-by-Step Solution:

1. **Identify the molecules**: The options given are NO, NO2, CO2, and ClO2.

2. **Calculate the total valence electrons for each molecule**:
- **NO (Nitric Oxide)**:
- Nitrogen (N) has 5 valence electrons.
- Oxygen (O) has 6 valence electrons.
- Total = 5 + 6 = 11 (odd number)

- **NO2 (Nitrogen Dioxide)**:
- Nitrogen (N) has 5 valence electrons.
- Oxygen (O) has 6 valence electrons, and there are 2 oxygen atoms.
- Total = 5 + (2 × 6) = 5 + 12 = 17 (odd number)

- **CO2 (Carbon Dioxide)**:
- Carbon (C) has 4 valence electrons.
- Oxygen (O) has 6 valence electrons, and there are 2 oxygen atoms.
- Total = 4 + (2 × 6) = 4 + 12 = 16 (even number)

- **ClO2 (Chlorine Dioxide)**:
- Chlorine (Cl) has 7 valence electrons.
- Oxygen (O) has 6 valence electrons, and there are 2 oxygen atoms.
- Total = 7 + (2 × 6) = 7 + 12 = 19 (odd number)

3. **Determine the presence of odd electron bonds**:
- For **NO**: 11 total electrons means there will be one unpaired electron.
- For **NO2**: 17 total electrons means there will be one unpaired electron.
- For **CO2**: 16 total electrons means all electrons are paired (no odd electron bond).
- For **ClO2**: 19 total electrons means there will be one unpaired electron.

4. **Conclusion**: The molecules that have odd electron bonds are NO, NO2, and ClO2. However, since the question asks for which has an odd electron bond, the answer is that odd electron bonds are present in NO, NO2, and ClO2.

### Final Answer:
Odd electron bonds are present in NO, NO2, and ClO2.