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Which of the following is non-polar...

Which of the following is non-polar

A

`H_2S`

B

`NaCl`

C

`Cl_2`

D

`H_2SO_4`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds is non-polar, we will analyze each option based on their molecular structure and the electronegativity of the atoms involved. ### Step-by-step Solution: 1. **Analyze H2S (Hydrogen Sulfide)**: - Sulfur (S) has 6 valence electrons and forms two bonds with hydrogen (H), using 2 of its electrons. - The remaining 4 electrons form 2 lone pairs on sulfur. - Sulfur is more electronegative than hydrogen, leading to a dipole moment where the electron density is pulled towards sulfur. - **Conclusion**: H2S is polar due to the difference in electronegativity and the presence of a dipole moment. 2. **Analyze NaCl (Sodium Chloride)**: - NaCl is an ionic compound formed from Na+ and Cl- ions. - There is a complete transfer of electrons from sodium to chlorine, resulting in a strong charge separation. - **Conclusion**: NaCl is polar due to the ionic nature and charge separation. 3. **Analyze Cl2 (Chlorine Gas)**: - Cl2 consists of two chlorine atoms bonded together. - Both atoms have the same electronegativity, leading to an equal sharing of electrons in the bond. - There is no charge separation since both atoms are identical. - **Conclusion**: Cl2 is non-polar as there is no dipole moment. 4. **Analyze H2SO4 (Sulfuric Acid)**: - H2SO4 has a complex structure with sulfur bonded to oxygen and hydrogen. - Oxygen is more electronegative than sulfur, leading to charge separation in the O-H and S=O bonds. - This results in a dipole moment, indicating polarity. - **Conclusion**: H2SO4 is polar due to the presence of charge separation and dipole moments. ### Final Answer: The non-polar compound among the options provided is **Cl2**.

To determine which of the given compounds is non-polar, we will analyze each option based on their molecular structure and the electronegativity of the atoms involved. ### Step-by-step Solution: 1. **Analyze H2S (Hydrogen Sulfide)**: - Sulfur (S) has 6 valence electrons and forms two bonds with hydrogen (H), using 2 of its electrons. - The remaining 4 electrons form 2 lone pairs on sulfur. - Sulfur is more electronegative than hydrogen, leading to a dipole moment where the electron density is pulled towards sulfur. ...
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