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The number of hybrid orbitals in a molec...

The number of hybrid orbitals in a molecule of decane are

A

36

B

40

C

38

D

8

Text Solution

Verified by Experts

The correct Answer is:
B
In decane each `sp^3` carbon has 4 hybrid orbitals
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The number of sp^(2) hybrid orbitals in a molecule of benzene is :

Number of hybrid orbitals present in a molecule of propene are

Spin pairing and overlapping theory cannot explain the equal bond length as well as equal bond angles in CH_(4) molecule. To explain the above facts we are in need of hybridization theory. Hybridization is the mixing of atomic orbitals of comparable energy and the numbe of atomic orbitals involved is equal to the number of hybrid orbitals formed of equal energy. Increasing order of the energy of hybrid orbitals is :

Spin pairing and overlapping theory cannot explain the equal bond length as well as equal bond angles in CH_(4) molecule. To explain the above facts we are in need of hybridization theory. Hybridization is the mixing of atomic orbitals of comparable energy and the numbe of atomic orbitals involved is equal to the number of hybrid orbitals formed of equal energy. The number of axial and equatorial positions in trigonal bipyramidal geometry having sp^(3)d hybridizaton are respectively :

Number of sp^2 hybrid orbitals in Benzene is

The type of hybridization in water molecule is

Hybridisation is the mixing of atomic orbital of comparable energy and the number of hybrid orbitals formed is equal to the number of pure atomic orbitals mixed up and hybrid orbitals are occupied by sigma -bond pair and lone pair. ''The hybrid orbitals are at at angle of X^(@) to one another''. This statement is not valid for which of the following hybridisation?

Hybridisation is the mixing of atomic orbital of comparable energy and the number of hybrid orbitals formed is equal to the number of pure atomic orbitals mixed up and hybrid are occupied by sigma -bond pair and lone pair. Which of the following geometry is most likely to not form from sp^(3)d hybridisation of the central atom.

Knowledge Check

  • Number of hybrid orbitals present in a molecule of propene are

    A
    12
    B
    10
    C
    9
    D
    8

  • Spin pairing and overlapping theory cannot explain the equal bond length as well as equal bond angles in CH_(4) molecule. To explain the above facts we are in need of hybridization theory. Hybridization is the mixing of atomic orbitals of comparable energy and the numbe of atomic orbitals involved is equal to the number of hybrid orbitals formed of equal energy. Increasing order of the energy of hybrid orbitals is :

    A
    `sp^(3)ltsp^(2)ltsp`
    B
    `sp^(2)ltsp^(3)ltsp`
    C
    `spltsp^(3)ltsp^(2)`
    D
    `spltsp^(2)ltsp^(3)`

  • Spin pairing and overlapping theory cannot explain the equal bond length as well as equal bond angles in CH_(4) molecule. To explain the above facts we are in need of hybridization theory. Hybridization is the mixing of atomic orbitals of comparable energy and the numbe of atomic orbitals involved is equal to the number of hybrid orbitals formed of equal energy. The number of axial and equatorial positions in trigonal bipyramidal geometry having sp^(3)d hybridizaton are respectively :

    A
    2, 4
    B
    4, 2
    C
    3, 3
    D
    2, 3