Number of hybrid orbitals present in a molecule of propene are

Options

A. 12
B. 10
C. 9
D. 8

Explanation

To determine the number of hybrid orbitals present in a molecule of propene (C3H6), we can follow these steps:

### Step 1: Understand the Structure of Propene
Propene is an alkene with the formula C3H6. It consists of three carbon atoms, with a double bond between the first and second carbon atoms. The structure can be represented as follows:
```
H H
\ /
C
/ \
H C = C
/ \
H H
```

### Step 2: Identify the Hybridization of Each Carbon Atom
- **First Carbon (C1)**: This carbon is bonded to three hydrogen atoms and one carbon atom (C2). It forms four sigma bonds, indicating it is **sp³ hybridized**.
- **Second Carbon (C2)**: This carbon is bonded to one hydrogen atom and two carbon atoms (C1 and C3). It forms three sigma bonds and one pi bond (due to the double bond with C1), indicating it is **sp² hybridized**.
- **Third Carbon (C3)**: This carbon is bonded to one hydrogen atom and one carbon atom (C2). It forms three sigma bonds, indicating it is **sp² hybridized**.

### Step 3: Count the Hybrid Orbitals
- **C1**: 4 sp³ hybrid orbitals (due to 4 sigma bonds).
- **C2**: 3 sp² hybrid orbitals (due to 3 sigma bonds).
- **C3**: 3 sp² hybrid orbitals (due to 3 sigma bonds).

### Step 4: Calculate the Total Number of Hybrid Orbitals
Now, we add the number of hybrid orbitals from each carbon:
- C1: 4 (sp³)
- C2: 3 (sp²)
- C3: 3 (sp²)

Total hybrid orbitals = 4 (from C1) + 3 (from C2) + 3 (from C3) = **10 hybrid orbitals**.

### Final Answer
The total number of hybrid orbitals present in a molecule of propene is **10**.

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