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The type of overlapping in Br-F bond in...

The type of overlapping in Br-F bond in `BrF_3` molecule is

A

`sp^3 - p`

B

`sp^2 - p`

C

`sp^3d-p`

D

`sp^3 - d^2 -p`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of overlapping in the Br-F bond in the `BrF_3` molecule, we can follow these steps: ### Step-by-Step Solution: 1. **Draw the Lewis Structure of BrF3**: - Bromine (Br) is the central atom, and it is bonded to three fluorine (F) atoms. - Each fluorine atom forms a single bond with bromine. - Bromine has 7 valence electrons, and after forming 3 bonds with fluorine, it has 4 electrons left, which will form 2 lone pairs. 2. **Determine the Hybridization of Bromine**: - Bromine has 2 lone pairs and 3 bond pairs (one for each Br-F bond). - The total number of electron pairs around bromine is 5 (2 lone pairs + 3 bond pairs). - The hybridization corresponding to 5 electron pairs is sp³d. 3. **Identify the Orbital of Fluorine Participating in Bonding**: - Fluorine has an atomic number of 9, with the electron configuration of 1s² 2s² 2p⁵. - In the bonding with bromine, the unpaired electron in the 2p orbital of fluorine will participate in the bond formation. 4. **Determine the Type of Overlapping**: - The overlapping occurs between the sp³d hybrid orbital of bromine and the p orbital of fluorine. - Therefore, the type of overlapping in the Br-F bond is sp³d-p overlapping. 5. **Conclusion**: - The type of overlapping in the Br-F bond in the `BrF_3` molecule is sp³d-p overlapping. ### Final Answer: The type of overlapping in the Br-F bond in `BrF_3` is **sp³d-p overlapping**. ---

To determine the type of overlapping in the Br-F bond in the `BrF_3` molecule, we can follow these steps: ### Step-by-Step Solution: 1. **Draw the Lewis Structure of BrF3**: - Bromine (Br) is the central atom, and it is bonded to three fluorine (F) atoms. - Each fluorine atom forms a single bond with bromine. - Bromine has 7 valence electrons, and after forming 3 bonds with fluorine, it has 4 electrons left, which will form 2 lone pairs. ...
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