If H - X bond length is `2Å` and H - X has dipole moment `5.12 xx 10^(-30)` coloumb.calculate the % of covalent character of molecule is

Options

A. 1
B. 16
C. 18
D. 84

Answer

To calculate the percentage of covalent character of the molecule HX, we will follow these steps:

### Step 1: Identify the given values
- Bond length (D) = 2 Å = \(2 \times 10^{-10}\) m
- Dipole moment (μ observed) = \(5.12 \times 10^{-30}\) C·m
- Charge of an electron (Q) = \(1.6 \times 10^{-19}\) C

### Step 2: Calculate the dipole moment (μ calculated)
The formula for calculating the dipole moment is given by:
\[ \mu_{\text{calculated}} = Q \times D \]
Substituting the values:
\[ \mu_{\text{calculated}} = (1.6 \times 10^{-19} \, \text{C}) \times (2 \times 10^{-10} \, \text{m}) \]
Calculating this gives:
\[ \mu_{\text{calculated}} = 3.2 \times 10^{-29} \, \text{C·m} \]

### Step 3: Calculate the percentage ionic character
Using the formula for percentage ionic character:
\[ \text{Percentage ionic character} = \left( \frac{\mu_{\text{observed}}}{\mu_{\text{calculated}}} \right) \times 100 \]
Substituting the values:
\[ \text{Percentage ionic character} = \left( \frac{5.12 \times 10^{-30}}{3.2 \times 10^{-29}} \right) \times 100 \]
Calculating this gives:
\[ \text{Percentage ionic character} = \left( 0.16 \right) \times 100 = 16\% \]

### Step 4: Calculate the percentage covalent character
To find the percentage covalent character, we subtract the percentage ionic character from 100%:
\[ \text{Percentage covalent character} = 100\% - \text{Percentage ionic character} \]
Substituting the value:
\[ \text{Percentage covalent character} = 100\% - 16\% = 84\% \]

### Final Answer
The percentage of covalent character of the molecule HX is **84%**.

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