20 `dm^(3)` of `SO_(2)` diffuse through a porous partition in 60 s. what volume of `O_(2)` will diffuse under similar conditions in 30 s ?

Options

A. `40 dm^(3)`
B. `10 dm^(3)`
C. `14.1 dm^(3)`
D. `28.2 dm^(3)`

Explanation

From Graham.s law , `(V_(1) // t_(1))/(V_(2) // t_(2)) = sqrt((M_(2))/(M_(1)))`
Given
`V_(1) = 20 dm^(3) " " t_(1) = 60 s M_1 = 64`
`V_(2) =? , t_(2) = 30 s M_(2) = 32`
`(20// 60)/(V_(2)//30) = sqrt((32)/(64)) implies V_(2) = 14.1 dm^(3)`.