A straight glass tube as shown, has 2 inleta X and Y at the two ends of 200 cm long tube. HCl gas through inlet X and `NH_(3)` gas through inlet Y are allowed to enter in the tube at the same time and pressure at a point P inside the tube. The distance of point P from X is:

Options

A. 100 cm
B. 81.1 cm
C. 75 cm
D. 90.1 cm

Explanation

Let distance of P from X end is a cm .

For diffusion of `NH_(3)` and HCl at same P
`(d_(NH_(3)))/(t_(NH_(3))) xx (t_(HCl))/(d_(HCl)) = sqrt(((M_(HCl))/(M_(NH_(3))))) , (200 - a)/(t) xx (t)/(a) = sqrt(((36.5)/(17))`
(Since time taken by both the gases are the same). `therefore` a = 81.1 cm so distance of P from the end of X is 81.1 cm