The cirtical constant for water are `374^(@)C` 218 atm and 0.0566 liter `mo1^(-1)` Calculate a,b and `R` .

Explanation

Given `T = 374^(@)C = 374 + 273 = 647` K
`P_c = 218` atm `, V_(c) = 0.0566` litre `mol^(-1)`
`because b = (V_(c))/(3) = (0.0566)/(3) = 0.0189` litre `mol^(-1)`
`a = 3 P_(c) V_(c)^(2) = 3 xx 218 xx (0.0566)^(2)`
`= 2.095 "litre"^(2)` atm `mol^(-2)`
`R = (8)/(3) (P_(c) T_(c))/(T_(c)) = (8 xx 218 xx 0.0566)/(3 xx 647)`
`= 0.05086` litre atm `K^(-1) mol^(-1)`