560 mL of oxygen gas (molar mass = 32 gm) at S.T.P contains `6 xx 10^(22)` molecules , 560 mL of sulphur dioxide gas (molar mass = 64 gm) at S.T.P contains the following number of molecules

Options

A. `6 xx 10^(22)`
B. `3 xx 10^(22)`
C. `12 xx 10^(22)`
D. `6 xx 10^(11)`

Answer

To solve the problem, we need to determine the number of molecules in 560 mL of sulfur dioxide (SO₂) gas at standard temperature and pressure (STP), given that 560 mL of oxygen (O₂) gas contains \(6 \times 10^{22}\) molecules.

### Step-by-Step Solution:

1. **Understand the Conditions**:
- Both gases are at STP, which is defined as a temperature of 273 K and a pressure of 1 atm.
- The volume of both gases is the same: 560 mL.

2. **Use Avogadro's Law**:
- Avogadro's law states that equal volumes of gases at the same temperature and pressure contain an equal number of molecules.
- Since both gases are at STP and occupy the same volume, they will contain the same number of molecules.

3. **Apply the Information Given**:
- We know that 560 mL of O₂ contains \(6 \times 10^{22}\) molecules.
- Since the conditions are the same for SO₂, it will also contain \(6 \times 10^{22}\) molecules.

4. **Conclusion**:
- Therefore, the number of molecules in 560 mL of sulfur dioxide gas at STP is also \(6 \times 10^{22}\).

### Final Answer:
560 mL of sulfur dioxide gas at STP contains \(6 \times 10^{22}\) molecules.

---