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S.I. unit of gas constant R is...

S.I. unit of gas constant R is

A

0.0821 litre atm `K^(-1) "mole"^(-1)`

B

2 calories `K^(-1) "mole"^(-1)`

C

8.31 joule `K^(-1) "mole"^(-1)`

D

None

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The correct Answer is:
To determine the SI unit of the gas constant \( R \), we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Ideal Gas Law**: The ideal gas law is given by the equation: \[ PV = nRT \] where \( P \) is the pressure, \( V \) is the volume, \( n \) is the number of moles, \( R \) is the gas constant, and \( T \) is the temperature. 2. **Rearranging the Equation**: To find the gas constant \( R \), we can rearrange the equation: \[ R = \frac{PV}{nT} \] 3. **Identify the Units**: - **Pressure (P)**: The SI unit of pressure is Pascal (Pa), which is equivalent to \( \text{N/m}^2 \) or \( \text{kg/(m \cdot s}^2) \). - **Volume (V)**: The SI unit of volume is cubic meter (m³). - **Number of moles (n)**: The SI unit for the amount of substance is mole (mol). - **Temperature (T)**: The SI unit of temperature is Kelvin (K). 4. **Substituting the Units into the Equation**: - Substitute the units into the rearranged equation for \( R \): \[ R = \frac{(Pa)(m^3)}{(mol)(K)} \] - Since \( 1 \, \text{Pa} = 1 \, \text{N/m}^2 = 1 \, \text{kg/(m \cdot s}^2) \), we can express \( R \) in terms of base SI units: \[ R = \frac{(kg/(m \cdot s^2))(m^3)}{mol \cdot K} \] - Simplifying this gives: \[ R = \frac{kg \cdot m^2}{s^2 \cdot mol \cdot K} \] 5. **Final SI Unit of R**: Therefore, the SI unit of the gas constant \( R \) is: \[ R = \frac{J}{mol \cdot K} \] where \( J \) (Joule) is the unit of energy. ### Conclusion: The SI unit of the gas constant \( R \) is \( \text{J/(mol} \cdot \text{K)} \).
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NARAYNA-STATES OF MATTER-EXERCISE - 1
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