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4.4 g of a gas at STP occupies a volume ...

4.4 g of a gas at STP occupies a volume of 2.24 L. The gas can be :

A

`O_2`

B

`CO`

C

`NO_2`

D

`CO_2`

Text Solution

Verified by Experts

The correct Answer is:
D
Molecular weight
`= (mRT)/(PV) = (4.4 xx .082 xx 273)/(1 xx 2.24) = 44`
So the gas should be `CO_(2)`
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