Containers `A` and `B` have same, gases. Pressure, volume and temperature of `A` are all twice that of `B`, then the ratio of number of molecules of `A` and `B` are

Options

A. `1 : 2`
B. `2 : 1`
C. `1 : 4`
D. `4 :1`

Answer

B

Explanation

According to gas law , `(p_(A) V_(A))/(n_(A) RT_(A)) = (p_(B) V_(B))/(n_(B) T_(B) R)`
or `(2 p xx 2 V)/(n_(A) R . 2T) = (pV)/(n_(B) RT) ` or `(n_(A))/(n_(B)) = (2)/(1)`
`because` No. of molecules = mole `xx` Avogadro number
`therefore ("Molecules of A")/("Molecules of B") = (n_(A) xx N_(A))/(n_(B) xx N_(A)) = (2 xx N_(A))/(1 xx N_(A)) = (2)/(1)`