The average veloctiy of an ideal gas molecule at `27^(@)C` is `0.3 m s^(-1)`. The average velocity at `927^(@)C` will be

Options

A. 0.6 m/sec
B. 0.3 m/sec
C. 0.9 m/sec
D. 3.0 m/sec

Answer

A

Explanation

`U_(av) mu sqrtT ` or `(U_(1))/(U_(2)) = sqrt((T_(1))/(T_(2))) = sqrt((300)/(1200)) = (1)/(2)`
`U_(2) = 2 xx U_(1) = 2 xx 0.3 = 0.6` m/sec